10x^2=480

Solution for 10x^2=480 equation:

10x^2=480

We move all terms to the left:

10x^2-(480)=0

a = 10; b = 0; c = -480;
Δ = b2-4ac
Δ = 02-4·10·(-480)
Δ = 19200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{19200}=\sqrt{6400*3}=\sqrt{6400}*\sqrt{3}=80\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{3}}{2*10}=\frac{0-80\sqrt{3}}{20}
=-\frac{80\sqrt{3}}{20}
=-4\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{3}}{2*10}=\frac{0+80\sqrt{3}}{20}
=\frac{80\sqrt{3}}{20}
=4\sqrt{3}
$